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The bookUnit 3 · Partial Differential Equations58 / 83

First-order PDE: Lagrange, Charpit, characteristics

Why this is asked: Write the characteristic ODEs, carry the initial data along them, and check whether characteristics cross — that crossing is what makes the solution fail to exist globally.

First-order PDE: characteristics, Lagrange and Charpit

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Lagrange's method on a first-order PDEinteractive

The auxiliary system, two first integrals, and the general solution — worked end to end.

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The trap here

“A first-order quasilinear Cauchy problem with smooth data has a global smooth solution” — false

uux+uy=0u u_{x} + u_y = 0 with u(x, 0) = −x

Characteristics x=x0(1y)x = x_{0}(1 - y) all meet at y = 1: the solution blows up in gradient (a shock).

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Check yourself

Let u(x, y) be the solution of the Cauchy problem uux+uy=0u\cdot{}u_{x} + u_y = 0 for xR,y>0x \in \mathbb{R}, y > 0, with u(x, 0) = x for xRx \in \mathbb{R}. Which of the following is the value of u(2, 3)?

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Open this in the full syllabus view · Unit 3