Counterexample

Is this true?

Every ordered field is Archimedean

No — it is false.

The counterexample

The object that kills this claim comes with Trap Analysis.

86 counterexamples are free — including most of the ones Part C leans on hardest.

Keep practicing

Standard counterexample

There is a canonical object that settles this. Recognising it is the whole question.

An arbitrary intersection of open sets is open

See real exam options built on this mistake Drill statements like this

Go deeper· Explained in full in The real line: supremum, Archimedes and density· Asked in CSIR NET December 2025· From The Real Line › Completeness, sup/inf, Archimedean property

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