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Counterexample

Is this true?

lim sup⁡(an+bn)=lim sup⁡an+lim sup⁡bn\limsup(a_{n} + b_{n}) = \limsup a_{n} + \limsup b_{n}

No — it is false.

The counterexample

an=(−1)n,bn=(−1)na_{n} = (-1)^{n}, b_{n} = (-1)^{n}⁺1^{1}

Why it fails

an+bn≡0a_{n} + b_{n} \equiv 0, so the left side is 0 while the right side is 1 + 1 = 2.

Keep practicing

Limit assumed to exist

Reasoning with a limit before establishing there is one. limsup is not lim.

Go deeper· Explained in full in limsup and liminf — three equivalent definitions and the algebra· Asked in CSIR NET December 2025· From The Real Line › limsup, liminf and subsequential limits

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