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Counterexample

Is this true?

∑anxn→L\sum{}a_{n}x^{n} \to L as x → 1⁻ ⇒∑an=L\Rightarrow \sum{}a_{n} = L

No — it is false.

The counterexample

∑(−1)nxn=1/(1+x)→1/2\sum(-1)^{n}x^{n} = 1/(1 + x) \to 1/2

Why it fails

∑(−1)n\sum(-1)^{n} diverges. Abel's theorem has no converse without a Tauberian condition.

Keep practicing

Boundary and endpoint

The statement turns at the edge of the interval, the domain, or the parameter range.

Go deeper· Explained in full in Power series — radius, boundary, Abel· Asked in CSIR NET December 2024· From Sequences and Series of Functions › Power series, radius of convergence, Abel's theorem

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