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Part CCSIR NET December 2024a-zero-on-the-border-kills-definiteness

A zero on the border kills definiteness

For a 4 × 4 positive definite real symmetric matrix A and real numbers a, b, c, d, consider the 5 × 5 matrix B whose first row is (0, a, b, c, d), whose first column is (0, a, b, c, d)ᵗ, and whose lower-right 4 × 4 block is A. Which of the following statements are necessarily true?

  1. A.det(B) > 0 for every nonzero (a,b,c,d)∈R4(a, b, c, d) \in \mathbb{R}^{4}.
  2. B.det(B) > 0 for infinitely many (a,b,c,d)∈R4(a, b, c, d) \in \mathbb{R}^{4}.
  3. C.det(B) ≤ 0 for every (a,b,c,d)∈R4(a, b, c, d) \in \mathbb{R}^{4}.✓ Correct
  4. D.det(B) ≤ 0 for infinitely many (a,b,c,d)∈R4(a, b, c, d) \in \mathbb{R}^{4}.✓ Correct

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests boundary and endpoint.

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50 are analysed free — try those first.

The trap it tests

Boundary and endpoint

The statement turns at the edge of the interval, the domain, or the parameter range.

Drill statements like this

Related counterexample: Every real symmetric matrix is positive definite if det > 0

More on this topic

The chapter behind this: Quadratic forms, signature and definiteness — free to read

From Inner Product Spaces and Forms › Quadratic forms, positive definiteness, Sylvester's law

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