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Part ACSIR NET December 2025bound-each-block-by-its-largest-term-not-by-its-term-count

Bound each block by its largest term not by its term count

The value of 1+(1/21+1/3)+(1/22+1/5+1/6+1/7)+⋯+(1/29+⋯+1/1023)1 + (1/2^{1} + 1/3) + (1/2^{2} + 1/5 + 1/6 + 1/7) + \dots + (1/2^{9} + \cdots + 1/1023) lies between

  1. A.2 and 10✓ Correct
  2. B.11 and 20
  3. C.21 and 30
  4. D.31 and 40

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests execution slip.

See pricing

50 are analysed free — try those first.

The trap it tests

Execution slip

The idea was right. The computation was not.

Drill statements like this

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

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