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Part BCSIR NET June 2024convergent-is-not-constant

Convergent is not constant

Let (an)n≥1(a_{n})_{n}\ge1 be a bounded sequence in R\mathbb{R}. Which of the following statements is FALSE?

  1. A.if liminfn→∞an=limsupn→∞anliminf_{n}\to\infty a_{n} = limsup_{n}\to\infty a_{n}, then (an)(a_{n}) is convergent
  2. B.if inf{ana_{n} | n ≥ 1} =limsupn→∞an= limsup_{n}\to\infty a_{n}, then (an)(a_{n}) is convergent
  3. C.if sup{ana_{n} | n ≥ 1} =liminfn→∞an= liminf_{n}\to\infty a_{n}, then (an)(a_{n}) is constant✓ Correct
  4. D.if sup{ana_{n} | n ≥ 1} = inf{ana_{n} | n ≥ 1}, then (an)(a_{n}) is constant

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests limit assumed to exist.

See pricing

50 are analysed free — try those first.

The trap it tests

Limit assumed to exist

Reasoning with a limit before establishing there is one. limsup is not lim.

Drill statements like this

Related counterexample: aₙ^{1/n} → L ⇒ aₙ₊₁/aₙ → L

More on this topic

The chapter behind this: Sequences in ℝ — the implication map — free to read

From The Real Line › Sequences: convergence, monotone, Bolzano–Weierstrass, Cauchy

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

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