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Part CCSIR NET June 2024irreducible-quotient-need-not-be-a-ufd

Irreducible quotient need not be a ufd

For two indeterminates x, y, let R = 𝔽 and S = R[y]. Which of the following statements are true?

  1. A.S is a principal ideal domain
  2. B. is a unique factorization domain
  3. C.S is a unique factorization domain
  4. D.S/(x) is a principal ideal domain

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward.

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50 are analysed free — try those first.

Related counterexample: Irreducible over ℤ ⇒ irreducible mod every prime

More on this topic

The chapter behind this: Irreducibility tests — free to read

From Rings and FieldsPolynomial rings and irreducibility tests

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