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Part BCSIR NET June 2024non-lipschitz-at-one-height-only

Non lipschitz at one height only

Consider the initial value problem (IVP)y′(x)=√) y'(x) = \surd|y(x)+εy(x) + \varepsilon|, x∈R,y(0)=y0x \in \mathbb{R}, y(0) = y_{0}. Consider the following statements: S1: There is an ε>0\varepsilon > 0 such that for all y0∈Ry_{0} \in \mathbb{R}, the IVP has more than one solution. S2: There is ay0∈Ra y_{0} \in \mathbb{R} such that for all ε>0\varepsilon > 0, the IVP has more than one solution. Then

  1. A.both S1S_{1} and S2S_{2} are true
  2. B.S1S_{1} is true but S2S_{2} is false
  3. C.S1S_{1} is false but S2S_{2} is true
  4. D.both S1S_{1} and S2S_{2} are false✓ Correct

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests existence vs uniqueness.

See pricing

50 are analysed free — try those first.

The trap it tests

Existence vs uniqueness

A theorem giving one was read as giving both.

Drill statements like this

Related counterexample: Every IVP has a unique solution

More on this topic

The chapter behind this: Existence, uniqueness and how far the solution extends — free to read

From Ordinary Differential Equations › Existence–uniqueness, Picard, Lipschitz

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

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