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Part BCSIR NET June 2025a-separable-kernel-turns-the-equation-into-one-scalar-unknown

A separable kernel turns the equation into one scalar unknown

If y(x) is the solution of the integral equation xt y(t) dt, then which of the following statements is true?

  1. A.y(0) + y(1) = 1/2
  2. B.y(−1) + y(1) = 1
  3. C.y′(0) + y′(1) = 3/2
  4. D.y′(−1) + y′(1) = 3

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests standard counterexample.

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50 are analysed free — try those first.

The trap it tests

Standard counterexample

There is a canonical object that settles this. Recognising it is the whole question.

Drill statements like this

Related counterexample: Volterra equations have eigenvalues just like Fredholm equations

More on this topic

The chapter behind this: Separable kernels and resolvent kernels — free to read

From Linear Integral EquationsSeparable kernels and resolvent kernels

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