Let B(v, w) be a nondegenerate symmetric bilinear form on and let q(v) = B(v, v) be the corresponding quadratic form. Suppose there exist vectors such that B(v, v) = 0 and B(v, w) ≠ 0. Which of the following statements are necessarily true?
Part CCSIR NET June 2025q-of-v-vanishing-makes-the-quadratic-in-alpha-linear-so-there-is-one-root-not-two
Q of v vanishing makes the quadratic in alpha linear so there is one root not two
Related counterexample: Every real symmetric matrix is positive definite if det > 0
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The chapter behind this: Quadratic forms, signature and definiteness — free to read
From Inner Product Spaces and Forms › Quadratic forms, positive definiteness, Sylvester's law