Part CCSIR NET June 2025the-riemann-sum-gives-the-logarithm-so-exponentiate-before-answering

The riemann sum gives the logarithm so exponentiate before answering

What is the value of the limit $l i m_{n \to \infty}$ (1/n)[(n + 1)(n + 2)⋯(n + n)] $^{1/ n}$ ?

A.2/e
B.4/e✓
C. $l o g_{e} 2 - 1$
D. $2 l o g_{e} 2 - 1$

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests execution slip.

See pricing

50 are analysed free — try those first.

The trap it tests

Execution slip

The idea was right. The computation was not.

Drill statements like this

Related counterexample: |f| Riemann integrable ⇒ f Riemann integrable

The riemann sum gives the logarithm so exponentiate before answering

More on this topic