Let u = u(x, y) be the solution of the boundary value problem ∂2u/∂x2+∂2u/∂y2=0 on (0, 1) × (0, 1), with u(x,0)=e(πx),u(x,1)=−e(πx) for x∈[0,1],u(0,y)=cos(πy)+sin(πy) and u(1,y)=eπ(cos(πy)+sin(πy)) for y ∈ [0, 1]. Then there exists a point (x0,y0)∈(0,1)×(0,1) such that
Multi-select · full marks only for the exact set · Partial Differential Equations