~ n, n cos(1/n) ~ n and n/log n all tend to , so each eventually exceeds any x. n ≤ 1/e is bounded, so it fails for x > 1/e.
Previous year questions
The complete June 2023 paper is solved and free to read — every question, with the reasoning behind each option.
Every PYQ solved, tagged by topic and trap type. Free samples are open; the full set needs the PYQ Pack.
2023 DecemberPart Cunbounded-vs-bounded-sequencesshow ▾Let x be a real number. Which of the following statements are true?
- A.There exists an integer n ≥ 1 such that .✓
- B.There exists an integer n ≥ 1 such that n cos(1/n) ≥ x.✓
- C.There exists an integer n ≥ 1 such that n ≥ x.
- D.There exists an integer n ≥ 2 such that n (log ≥ x.✓
Solution
Topic: The Real Line › Sequences: convergence, monotone, Bolzano–Weierstrass, Cauchy
2023 DecemberPart Cinjective-continuous-implies-monotoneshow ▾Locked — Continuity and Differentiation. Unlock the PYQ Pack
2023 DecemberPart Cperiodic-uniform-continuityshow ▾Let be the periodic function of period 1 given by f(x) = 1 − |2x − 1| for x ∈ [0, 1], and define by . Which of the following statements are true?
- A.f is continuous on .✓
- B.f is uniformly continuous on .✓
- C.g is continuous on .✓
- D.g is uniformly continuous on .
Solution
f is a continuous tent function with f(0) = f(1) = 0, so its periodic extension is continuous; continuous periodic ⇒ uniformly continuous. g = f∘ is continuous but its oscillations speed up as the tents get compressed), so it is not uniformly continuous.
Topic: Continuity and Differentiation › Continuity, uniform continuity, Lipschitz
2023 DecemberPart Cp-integral-thresholdsshow ▾For a real number , consider the improper integrals dx and dx. Which of the following statements are true?
- A.There exists such that converges, but does not converge.✓
- B.There exists such that converges, but does not converge.✓
- C.There exists such that both converge.
- D.There exists such that neither nor converges.✓
Solution
converges iff converges iff . So they never converge together, and at neither does.
2023 DecemberPart Cmoments-determine-functionshow ▾Locked — Integration. Unlock the PYQ Pack
2023 DecemberPart Cvanishing-factor-at-endpointshow ▾Locked — Sequences and Series of Functions. Unlock the PYQ Pack
2023 DecemberPart Cshow ▾For real numbers a, b, c, d, e, f, consider the function given by F(x, y) = (ax + by + c, dx + ey + f). Which of the following statements are true?
- A.F is continuous.✓
- B.F is uniformly continuous.✓
- C.F is differentiable.✓
- D.F has partial derivatives of all orders.✓
Solution
An affine map is Lipschitz (hence uniformly continuous), differentiable with constant derivative, and all higher partials are zero.
Topic: Functions of Several Variables › Partial derivatives, differentiability, chain rule
2023 DecemberPart Cmonotone-not-necessarily-increasingshow ▾Locked — Functions of Several Variables. Unlock the PYQ Pack
2023 DecemberPart Cprojection-is-open-mapshow ▾Locked — Functions of Several Variables. Unlock the PYQ Pack
2023 DecemberPart Cpartition-counterexamplesshow ▾Locked — Lebesgue Measure and Integration. Unlock the PYQ Pack
2023 DecemberPart Cnilpotent-index-from-nullityshow ▾Locked — Vector Spaces and Linear Maps. Unlock the PYQ Pack
2023 DecemberPart Cunion-of-subspacesshow ▾Locked — Vector Spaces and Linear Maps. Unlock the PYQ Pack
2023 DecemberPart Ccayley-hamilton-remaindershow ▾Locked — Eigenvalues and Canonical Forms. Unlock the PYQ Pack
2023 DecemberPart Cinvertibility-from-matrix-identityshow ▾Locked — Eigenvalues and Canonical Forms. Unlock the PYQ Pack
2023 DecemberPart Cshow ▾Let A be an n × n real symmetric matrix. Which of the following statements are necessarily true?
- A.A is diagonalizable.✓
- B.If Aᵏ = I for some positive integer k, then .✓
- C.If Aᵏ = 0 for some positive integer k, then .✓
- D.All eigenvalues of A are real.✓
Solution
Spectral theorem: A = QDQᵀ with real D. Aᵏ = I forces each real eigenvalue to satisfy , so and forces all so A = 0.
Topic: Eigenvalues and Canonical Forms › Eigenvalues, characteristic & minimal polynomials, Cayley–Hamilton
2023 DecemberPart Creading-jordan-blocksshow ▾Locked — Eigenvalues and Canonical Forms. Unlock the PYQ Pack
2023 DecemberPart Cshow ▾Locked — Inner Product Spaces and Forms. Unlock the PYQ Pack
2023 DecemberPart Cgaussian-integersshow ▾Locked — Rings and Fields. Unlock the PYQ Pack
2023 DecemberPart Cshow ▾Let be such that n ≡ 1 (mod 7) and n ≡ 4 (mod 15). Which of the following statements are true?
- A.n ≡ 1 (mod 3).✓
- B.n ≡ 1 (mod 35).
- C.n ≡ 1 (mod 21).✓
- D.n ≡ 1 (mod 5).
Solution
n ≡ 4 (mod 15) gives n ≡ 1 (mod 3) and n ≡ 4 (mod 5). With n ≡ 1 (mod 7), CRT gives n ≡ 1 (mod 21); n ≢ 1 (mod 5) kills the mod-35 claim.
Topic: Rings and Fields › Ideals, quotient rings, prime & maximal ideals, CRT
2023 DecemberPart Cirreducible-over-Q-not-mod-pshow ▾Locked — Rings and Fields. Unlock the PYQ Pack
2023 DecemberPart Corder-of-gl2-over-z-9show ▾Locked — Groups. Unlock the PYQ Pack
2023 DecemberPart Cshow ▾Let and let be the splitting field of f(X) over . Let . Which of the following statements are true?
- A.The Galois group of K over is the symmetric group .✓
- B.The Galois group of K over is the symmetric group .
- C.The Galois group of K over is .
- D.The Galois group of K over is .✓
Solution
has degree 6 over with non-abelian Galois group ; over the degree is 3, so the group is .