Standard spaces: cofinite, cocountable, Sorgenfrey, Cantor set
Why this is asked: These four spaces are the exam's stock counterexamples — memorise the property table and you can answer most 'which of the following is true' topology items by elimination.
The property table
| Property | Cofinite on | Cocountable on | Sorgenfrey | Cantor set |
|---|---|---|---|---|
| ✓ | ✓ | ✓ | ✓ | |
| Hausdorff | ✗ | ✗ | ✓ | ✓ |
| compact | ✓ | ✗ | ✗ | ✓ |
| connected | ✓ | ✓ | ✗ | ✗ |
| separable | ✓ | ✗ | ✓ | ✓ |
| first countable | ✗ | ✗ | ✓ | ✓ |
| second countable | ✗ | ✗ | ✗ | ✓ |
| metrizable | ✗ | ✗ | ✗ | ✓ |
| normal | ✓ | ✓ | ✓ (square is not) | ✓ |
Cofinite topology
Open = ∅ or complement of a finite set. On an infinite set: but not Hausdorff, compact, connected, and every injective map into it is continuous. Convergence is strange: every sequence of distinct points converges to every point.
Sorgenfrey line
Base [a, b). Finer than the usual topology. Separable, first countable, Lindelöf, normal, totally disconnected — but not second countable and not metrizable. Its square is separable but contains an uncountable discrete subspace, so is not normal: the standard counterexample to "product of normal is normal".
Cantor set
Compact, perfect (no isolated points), totally disconnected, uncountable, measure zero, nowhere dense, homeomorphic to {0,1}Every** compact metric totally disconnected perfect space is homeomorphic to it.
Key takeaways
- Need "compact but not Hausdorff"? Cofinite. "Connected but not Hausdorff"? Cofinite.
- Need "normal but square not normal"? Sorgenfrey.
- Need "uncountable but measure zero"? Cantor.
See it move
Check yourself — select all that apply
Let X be an infinite set with the cofinite topology. Which of the following are true?
Next: Existence–uniqueness, Picard, Lipschitz
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Open this in the full syllabus view · Unit 2