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Neyman–Pearson lemma and UMP tests

Why this is asked: NP gives the most powerful test for simple-vs-simple; monotone likelihood ratio upgrades it to UMP for one-sided alternatives. Two-sided alternatives usually have no UMP test.

Neyman–Pearson lemma

For H0:θ=θ0H_{0}: \theta = \theta_{0} vs H1:θ=θ1(H_{1}: \theta = \theta_{1} (both simple), the most powerful sizeα-\alpha test rejects when

L(θ1)/L(θ0)>kL(\theta_{1})/L(\theta_{0}) > k, with k chosen so the size is α\alpha.

From MP to UMP

If the family has monotone likelihood ratio in T (exponential families do), then the one-sided test "reject if T > c" is UMP for H0:θθ0H_{0}: \theta \le \theta_{0} vs H1:θ>θ0H_{1}: \theta > \theta_{0}.

Two-sided alternatives generally admit no UMP test — the best one-sided tests point in opposite directions. One then uses UMP unbiased tests or the likelihood ratio test.

Direction matters

If larger θ\theta makes T smaller, the rejection region flips. For a Gamma(4,λ)(4, \lambda) sample, T=XiT = \sum{}X_{i} has 2λT2\lambda{}T ~ χ4n2\chi^{2}_{4n}, and larger λ\lambda shrinks T, so the UMP test for λ>1\lambda > 1 rejects for small T.

Size and power

  • Size = P(reject | H0)H_{0}); power = P(reject | H1)=1βH_{1}) = 1 - \beta.
  • Power increases with n, with |θ1θ0\theta_{1} - \theta_{0}|, and with α\alpha.
  • A test with power < size is worse than random (biased test).

Likelihood ratio test

Λ=\Lambda = supΘ0sup_{\Theta_{0}} L/supΘLL / sup_\Theta L; reject for small Λ\Lambda. Under regularity, 2lnΛχr2**-2 \ln \Lambda \to \chi^{2}_r** where r = the number of restricted parameters (Wilks). This is the general-purpose test when no UMP exists.

Key takeaways

  • NP: simple vs simple, likelihood ratio, threshold from the size.
  • MLR ⇒ one-sided UMP; two-sided usually has none.
  • Check whether the statistic increases or decreases with the parameter before writing the rejection region.

See it move

Type I against Type II: the trade-off you cannot escapeinteractivefree

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The trap here

“A UMP test exists for every testing problem” — false

H0:μ=0H_{0}: \mu = 0 vs H1:μ0H_{1}: \mu \ne 0 for N(μ,1)N(\mu, 1)

The MP test for μ>0\mu > 0 rejects for large X̄, for μ<0\mu < 0 for small X̄; no single test is best against both.

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Next: Likelihood ratio and standard tests

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