CRD, RBD, LSD essentials
Why this is asked: Degrees of freedom are the most-asked item: CRD N − k, RBD (k−1)(r−1), LSD (p−1)(p−2). Blocking removes a nuisance source and costs error degrees of freedom.
The three basic designs
| Design | Model | Error d.f. | Controls |
|---|---|---|---|
| CRD | N − k | nothing | |
| RBD | (k−1)(r−1) | one nuisance factor | |
| LSD (p×p) | (p−1)(p−2) | two nuisance factors |
In an LSD the number of treatments equals the number of rows and columns (p), and units are used. If the error d.f. is 42, then (p−1)(p−2) = 42 gives p = 8, so treatments have 7 d.f.
ANOVA table shape
Total d.f. = N − 1, split into treatment, block(s) and error. The F statistic is MS_treatment/MS_error with (k−1, error) degrees of freedom.
Principles
- Randomisation removes bias; replication gives an error estimate; local control (blocking) removes a known source of variability.
- Blocking increases precision only if the blocks really differ — otherwise you have merely lost error degrees of freedom.
- Relative efficiency of RBD to CRD = (MSE_CRD/MSE_RBD), adjusted for d.f.
Factorial experiments
factorial estimates main effects and interactions; confounding sacrifices a high-order interaction to reduce block size. Effects are estimated by contrasts of the treatment totals.
Missing plot
For one missing value in an RBD: ŷ = (rB + kT − G)/((r−1)(k−1)), and the error d.f. drops by one.
Key takeaways
- Memorise the three error d.f. formulas — they are asked directly.
- LSD: p treatments, , two nuisance directions.
- Blocking trades error d.f. for reduced error variance; it only pays if blocks differ.
See it move
Check yourself
In a Latin square design, the degrees of freedom for the error sum of squares is 42. Then the degrees of freedom for the sum of squares due to treatments is
Check yourself
In a randomised block design with 5 treatments and 4 blocks, the error degrees of freedom is
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