NETMaths
Part BCSIR NET December 2023

CRD, RBD, LSD essentials

In a Latin square design, the degrees of freedom for the error sum of squares is 42. Then the degrees of freedom for the sum of squares due to treatments is

  1. A.6
  2. B.7
  3. C.8
  4. D.9

Solution

For a p × p Latin square the error d.f. is (p − 1)(p − 2) = 42 ⇒ p = 8, so treatments have p − 1 = 7 d.f.

From Sampling and Design of ExperimentsCRD, RBD, LSD essentials

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