Skip to content
Counterexample

Is this true?

Cauchy's theorem applies to any domain without singularities of f

No — it is false.

The counterexample

f(z) = 1/z on the annulus ½ < |z| < 2

Why it fails

f is holomorphic there but ∮∣z∣=1\oint_{|z|=1} dz/z=2πi≠0/z = 2\pi{}i \ne 0 — the annulus is not simply connected.

Go deeper· Explained in full in Cauchy's theorem and integral formula — the toolkit· Asked in CSIR NET December 2024· From Cauchy Theory › Cauchy's theorem and integral formula

Published . Found a mistake? Tell us — corrections are the fastest thing we act on.

ShareWhatsAppTelegram