NETMaths

Is this true?

Every boundary value problem has a Green's function

No — it is false.

The counterexample

on [0,1] with y(0) = y(1) = 0

is an eigenvalue of the homogeneous problem, so the operator is not invertible and no Green's function exists.

The kind of mistake this is

Hypothesis dropped

A theorem applied without checking one of its preconditions.

Drill statements like this

Others that fail the same way

From Ordinary Differential EquationsSturm–Liouville problems and Green's functions

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