Not Lipschitz at 0; y ≡ 0 and y = both solve it.
Counterexample bank
Part C is won by knowing which tempting claims are false. 148 counterexamples; 85 free. The rest come with the Notes pack.
#1 · ODE, PDE & Applied Mathematics › Ordinary Differential Equations
“Every IVP has a unique solution” — false
Counterexample: y′ = y^{1/3}, y(0) = 0
#2 · ODE, PDE & Applied Mathematics › Ordinary Differential Equations
“A continuous right-hand side gives a unique solution” — false
Counterexample: y′ = y^{1/3}, y(0) = 0
Not Lipschitz at 0: y ≡ 0 and y = both solve it, as do infinitely many hybrids.
#3 · ODE, PDE & Applied Mathematics › Ordinary Differential Equations
“A locally unique solution exists for all time” — false
Counterexample locked — unlock with Notes + PYQ
#4 · ODE, PDE & Applied Mathematics › Ordinary Differential Equations
“W(f, g) ≡ 0 implies f and g are linearly dependent” — false
Counterexample: f(x) = x², g(x) = x|x| on ℝ
The Wronskian vanishes identically but no constant multiple relates them. The implication holds only for solutions of a common linear ODE.
#5 · ODE, PDE & Applied Mathematics › Ordinary Differential Equations
“Every boundary value problem has a Green's function” — false
Counterexample: y″ + π²y = f on [0,1] with y(0) = y(1) = 0
is an eigenvalue of the homogeneous problem, so the operator is not invertible and no Green's function exists.
#6 · ODE, PDE & Applied Mathematics › Ordinary Differential Equations
“Linearisation determines stability at every equilibrium” — false
Counterexample: ẋ = −y − x³, ẏ = x − y³ at the origin
The linearisation is a centre (eigenvalues ±i), but gives V̇ : asymptotically stable. Non-hyperbolic equilibria escape Hartman–Grobman.