NETMaths

Is this true?

If all partial derivatives exist at a point then f is continuous there

No — it is false.

The counterexample

f(x,y) = xy

Both partials are 0 at the origin, but f = ½ along y = x, so f is not continuous.

The kind of mistake this is

Converse assumed

The theorem runs one way. You used it in the other.

Drill statements like this

Others that fail the same way

From Functions of Several VariablesPartial derivatives, differentiability, chain rule

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