Both partials are 0 at the origin, but f = ½ along y = x, so f is not continuous.
Counterexample bank
Part C is won by knowing which tempting claims are false. 148 counterexamples; 85 free. The rest come with the Notes pack.
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#1 · Analysis & Linear Algebra › Functions of Several Variables
“If all partial derivatives exist at a point then f is continuous there” — false
Counterexample: f(x,y) = xy/(x²+y²), f(0,0) = 0
multivariable
#2 · Analysis & Linear Algebra › Functions of Several Variables
“Mixed partial derivatives are always equal” — false
Counterexample locked — unlock with Notes + PYQ
multivariable
#3 · Analysis & Linear Algebra › Functions of Several Variables
“A C¹ map with everywhere non-zero Jacobian is injective” — false
Counterexample: f(x,y) = (eˣ cos y, eˣ sin y) on ℝ²
The Jacobian determinant is ≠ 0, but . Invertibility is only local.
multivariable