|f| ≡ 1 is integrable; f is discontinuous everywhere.
Counterexample bank
Part C is won by knowing which tempting claims are false. 148 counterexamples; 85 free. The rest come with the Notes pack.
#1 · Analysis & Linear Algebra › Integration
“Riemann integrable ⇒ continuous almost everywhere fails for… (i.e. 'bounded ⇒ integrable')” — false
Counterexample locked — unlock with Notes + PYQ
#2 · Analysis & Linear Algebra › Integration
“|f| Riemann integrable ⇒ f Riemann integrable” — false
Counterexample: f = 1 on ℚ ∩ [0,1], −1 elsewhere
#3 · Analysis & Linear Algebra › Integration
“A composition of Riemann integrable functions is Riemann integrable” — false
Counterexample locked — unlock with Notes + PYQ
#4 · Analysis & Linear Algebra › Sequences and Series of Functions
“fₙ → 0 pointwise on [0,1] ⇒ ∫₀¹ fₙ → 0” — false
Counterexample locked — unlock with Notes + PYQ
#5 · Analysis & Linear Algebra › Integration
“If ∫₀^∞ f converges then f(x) → 0” — false
Counterexample: f with a spike of height n and width 2/n³ at each integer n
The total area is finite but f is unbounded, so it does not tend to 0.
#6 · Analysis & Linear Algebra › Lebesgue Measure and Integration
“Pointwise convergence implies convergence of the integrals” — false
Counterexample: fₙ = n·1_{(0,1/n)} on [0,1]
pointwise but always. Domination or monotonicity is essential.