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Part BCSIR NET December 2024agreement-on-a-line-propagates-by-reflection

Agreement on a line propagates by reflection

For z = x + iy ∈C\in \mathbb{C}, let f(z) = u(x, y) + iv(x, y) define an entire function. Consider the function g(z) = u(x, −y) − iv(x, −y), for z = x + iy ∈C\in \mathbb{C}. Suppose that v(x, 0) = 0 for all x∈Rx \in \mathbb{R}. Define E = {z∈Cz \in \mathbb{C} | f(z) = g(z)}. Which of the following statements is true?

  1. A.E is the real axis.
  2. B.E is the imaginary axis.
  3. C.E contains an open subset of C\mathbb{C}, but E≠CE \ne \mathbb{C}.
  4. D.E=CE = \mathbb{C}✓ Correct

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests standard counterexample.

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50 are analysed free — try those first.

The trap it tests

Standard counterexample

There is a canonical object that settles this. Recognising it is the whole question.

Drill statements like this

Related counterexample: A harmonic function on any domain has a harmonic conjugate

More on this topic

The chapter behind this: Cauchy–Riemann — what they do and do not give you — free to read

From Analytic Functions › Cauchy–Riemann equations, harmonic functions

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