In plain words
A real map of the plane has four derivatives to play with. A complex derivative is one number, and these two equations force four down to one — a rotation with a scaling.
The equations
f = u + iv is complex differentiable at iff f is real-differentiable there and . Then iv.
| Hypothesis | Conclusion |
|---|---|
| CR hold at a single point + real-differentiable there | f′ exists at that point |
| CR hold on an open set and partials are continuous | f is holomorphic there (Goursat: continuity is automatic) |
| CR hold on an open set, partials merely exist | not enough |
The classic spoiler: for z ≠ 0, f(0) = 0 satisfies the CR equations at 0 but is not differentiable at 0 (the limit depends on the direction of approach).
Consequences worth quoting
- f holomorphic with f′ ≡ 0 on a domain (connected open set) ⇒ f constant. Connectedness is essential.
- Any of these forces a holomorphic f on a domain to be constant: |f| constant, Re f constant, Im f constant, arg f constant, f̄ holomorphic, f real-valued.
- u and v are harmonic and are harmonic conjugates; the level curves and meet orthogonally where . for holomorphic .
- A harmonic conjugate exists on any simply connected domain. On an annulus it can fail: u = log|z| has no single-valued conjugate on ∖{0}.
Anti-holomorphic traps
If f is entire then:
- z ↦ conj(f(z̄)) is entire (conjugate the coefficients);
- z ↦ f(z̄) and z ↦ conj(f(z)) are anti-holomorphic — entire only when f is constant.
Key takeaways
- CR at a point ≠ holomorphic at a point; you need real-differentiability too.
- Any "constant modulus / constant real part / conjugate also holomorphic" hypothesis collapses f to a constant.
- conj(f(z̄)) is the one conjugation that preserves holomorphy.