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Part BCSIR NET December 2024the-components-do-not-overlap-so-y-is-observed

The components do not overlap so y is observed

Let X and Y be independent random variables such that X follows U(0, 1) distribution and Y follows Bernoulli distribution with success probability p ∈ (0, 1). Define Z = X + Y. Let z1=0.5,z2=1.2,z3=1.3,z4=0.9,z5=0.1,z6=0.7z_{1} = 0.5, z_{2} = 1.2, z_{3} = 1.3, z_{4} = 0.9, z_{5} = 0.1, z_{6} = 0.7 be the observed values from the distribution of Z. Then the maximum likelihood estimate of p equals

  1. A.1/4
  2. B.1/2
  3. C.1/3✓ Correct
  4. D.1/6

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests execution slip.

See pricing

50 are analysed free — try those first.

The trap it tests

Execution slip

The idea was right. The computation was not.

Drill statements like this

Related counterexample: The MLE is unbiased

More on this topic

The chapter behind this: Maximum likelihood and the method of moments — free to read

From Estimation › MLE and method of moments

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