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Part BCSIR NET December 2024the-operator-space-has-square-dimension

The operator space has square dimension

Let V be a vector space over R\mathbb{R}. Let T1,T2:V→VT_{1}, T_{2} : V \to V be two R−\mathbb{R}-linear transformations such that T1+T2T_{1} + T_{2} and T1−T2T_{1} - T_{2} are linearly independent over R\mathbb{R}. Consider the following statements: (A) The transformations T1T_{1} and T2T_{2} are linearly independent over R.(B)\mathbb{R}. (B) There exist R−\mathbb{R}-linear transformations T3,T4:V→VT_{3}, T_{4} : V \to V such that {T1+T2,T1−T2,T3,T4T_{1} + T_{2}, T_{1} - T_{2}, T_{3}, T_{4}} is linearly independent over R\mathbb{R}. Which of the following statements is true?

  1. A.(A) is true but (B) is false.
  2. B.(B) is true but (A) is false.
  3. C.Both (A) and (B) are true.✓ Correct
  4. D.Both (A) and (B) are false.

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests finite-dimensional intuition.

See pricing

50 are analysed free — try those first.

The trap it tests

Finite-dimensional intuition

Something true in ℝⁿ, or in a nice space, assumed in general.

Drill statements like this

Related counterexample: Equivalent matrices are similar

More on this topic

The chapter behind this: Linear transformations, matrices and similarity — free to read

From Vector Spaces and Linear Maps › Linear transformations, matrix representation, change of basis

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

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