Skip to content
Part BCSIR NET December 2024the-schur-complement-loses-one-degree-of-freedom

The schur complement loses one degree of freedom

Let X, Y and Z be random variables such that S = [[X, Y], [Y, Z]] ~ , where denotes the Wishart distribution and . Define . Then, Var(T) equals

  1. A.77/6
  2. B.81/8
  3. C.83/9
  4. D.79/7

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward.

See pricing

50 are analysed free — try those first.

Related counterexample: If every marginal is normal then the vector is multivariate normal

More on this topic

The chapter behind this: Multivariate normal and Wishart — free to read

From Linear Models and MultivariateMultivariate normal distribution

ShareWhatsAppTelegram