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Part CCSIR NET December 2024the-two-norms-are-not-equivalent

The two norms are not equivalent

Consider the real vector space X = {f:[0,1]→Rf : [0, 1] \to \mathbb{R} | f is continuous}, along with the norms ‖·‖1_{1} and ‖·‖2_{2} defined by ‖f‖1=∫01_{1} = \int_{0}^{1}|f(x)|dx and ‖f‖2=(∫01_{2} = (\int_{0}^{1}|f(x)|2^{2}dx)^(1/2). For n ≥ 1 and x ∈ [0, 1], let fn(x)=f_{n}(x) = nxn^{n}. Which of the following statements are true?

  1. A.(‖fnf_{n}‖1)_{1}) is a convergent sequence.✓ Correct
  2. B.(‖fnf_{n}‖2)_{2}) is a convergent sequence.
  3. C.Both (‖fnf_{n}‖1)_{1}) and (‖fnf_{n}‖2)_{2}) are convergent sequences.
  4. D.Neither (‖fnf_{n}‖1)_{1}) nor (‖fnf_{n}‖2)_{2}) is a convergent sequence.

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests finite-dimensional intuition.

See pricing

50 are analysed free — try those first.

The trap it tests

Finite-dimensional intuition

Something true in ℝⁿ, or in a nice space, assumed in general.

Drill statements like this

Related counterexample: L¹[0,1] ⊆ L²[0,1]

More on this topic

The chapter behind this: L^p spaces: inequalities and inclusions — free to read

From Lebesgue Measure and Integration › L^p spaces essentials

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

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