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Part CCSIR NET June 2023transport-equation-data-on-a-line

Transport equation data on a line

Let u:R2→Ru : \mathbb{R}^{2} \to \mathbb{R} solve ∂xu+2∂yu=0\partial_{x}u + 2\partial_yu = 0 on R2\mathbb{R}^{2} with u(x, y) = sin x on the line y = 3x + 1, and let v:R2→Rv : \mathbb{R}^{2} \to \mathbb{R} solve ∂xv+2∂yv=0\partial_{x}v + 2\partial_yv = 0 with v(x, 0) = sin x. Let S = [0,1] × [0,1]. Which of the following statements are true?

  1. A.u changes sign in the interior of S.
  2. B.u(x, y) = v(x, y) along a line in S.✓ Correct
  3. C.v changes sign in the interior of S.✓ Correct
  4. D.v vanishes along a line in S.✓ Correct

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests execution slip.

See pricing

50 are analysed free — try those first.

The trap it tests

Execution slip

The idea was right. The computation was not.

Drill statements like this

Related counterexample: A first-order quasilinear Cauchy problem with smooth data has a global smooth solution

More on this topic

The chapter behind this: First-order PDE: characteristics, Lagrange and Charpit — free to read

From Partial Differential Equations › First-order PDE: Lagrange, Charpit, characteristics

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