Part BCSIR NET June 2025e-is-the-limit-inside-the-log-so-the-function-tends-to-1

E is the limit inside the log so the function tends to 1

Let $f (x) = x l o g_{e} (1 + 1/ x)$ for $x \in (0, \infty)$ . Which of the following statements is true?

A.f is unbounded.
B.f is increasing.✓
C. $l i m_{x \to \infty}$ f(x) = 2.
D.f is decreasing.

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests execution slip.

See pricing

50 are analysed free — try those first.

The trap it tests

Execution slip

The idea was right. The computation was not.

Drill statements like this

Related counterexample: Differentiable ⇒ continuously differentiable

E is the limit inside the log so the function tends to 1

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