Skip to content
Counterexample

Is this true?

f′(x0)=0f'(x_{0}) = 0 and f′ changes sign nowhere near x0⇒fx_{0} \Rightarrow f is constant near x0x_{0}

No — it is false.

The counterexample

The object that kills this claim comes with Trap Analysis.

See pricing

86 counterexamples are free — including most of the ones Part C leans on hardest.

Go deeper· Explained in full in Differentiation — MVT, Darboux, Taylor and the classic spoilers· Asked in CSIR NET June 2025· From Continuity and Differentiation › Differentiability, mean value theorems, Taylor, L'Hôpital

ShareWhatsAppTelegram