NETMaths

Is this true?

Uniformly continuous ⇒ Lipschitz

No — it is false.

The counterexample

This one comes with the Notes pack.

See pricing

85 counterexamples are free — including most of the ones Part C leans on hardest.

The kind of mistake this is

Hypothesis dropped

A theorem applied without checking one of its preconditions.

Drill statements like this

Watch it happen

The ε–δ limit machine

Others that fail the same way

From Continuity and DifferentiationContinuity, uniform continuity, Lipschitz

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