Consider the following real-valued functions and defined on , given by if x≥1, 0 otherwise, and ˣexp(−t)dt if x≥0, 0 otherwise. Define another function by for all . Which of the following statements are true?
Part CCSIR NET December 2025f2-is-continuous-everywhere-so-it-cannot-mask-f1-s-jump-at-x-equals-1-only-right-continuity-survives
F2 is continuous everywhere so it cannot mask f1 s jump at x equals 1 only right continuity survives
Related counterexample: Continuous on a bounded interval ⇒ bounded
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The chapter behind this: Continuity vs uniform continuity vs Lipschitz — free to read
From Continuity and Differentiation › Continuity, uniform continuity, Lipschitz
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