NETMaths
The bookUnit 1 · Continuity and Differentiation5 / 83

Continuity, uniform continuity, Lipschitz

Why this is asked: The chain Lipschitz ⇒ uniformly continuous ⇒ continuous, where each converse fails, and what compactness or boundedness of the domain changes. Know √x, 1/x, x², sin(1/x), sin(x²) by heart.

Continuity vs uniform continuity vs Lipschitz

The written notes for this page come with the Notes pack. The video, the visual and the practice below are free.

See pricing

See it move

The ε–δ limit machineinteractivefree

Scroll to load…

The trap here

“Continuous on a bounded interval ⇒ bounded” — false

f(x) = 1/x on (0,1)

Needs a compact (closed) domain.

More on this →

Check yourself — select all that apply

Which of the following functions are uniformly continuous on the given domain?

Next: Differentiability, mean value theorems, Taylor, L'Hôpital

Create a free account to keep your place and have this feed your study plan.

Open this in the full syllabus view · Unit 1