NETMaths

Is this true?

Bounded and continuous on uniformly continuous

No — it is false.

The counterexample

satisfy || → 0 while || = 1.

The kind of mistake this is

Hypothesis dropped

A theorem applied without checking one of its preconditions.

Drill statements like this

Watch it happen

The ε–δ limit machine

Others that fail the same way

From Continuity and DifferentiationContinuity, uniform continuity, Lipschitz

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