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Part CCSIR NET June 2025the-kernel-vanishes-on-the-diagonal-so-three-derivatives-give-a-clean-ode

The kernel vanishes on the diagonal so three derivatives give a clean ode

Let u(x) be the solution to the Volterra integral equation u(x)=x2+4∫0u(x) = x^{2} + 4\int_{0}ˣ (t−x)2u(t)(t - x)^{2}u(t) dt. Then which of the following statements are true?

  1. A.u(0) = 0✓ Correct
  2. B.u(2π/3)=u(2\pi/\sqrt{3}) = (1/6)(e4π/3(1/6)(e^{4\pi/\sqrt{3}} − e−2π/3)e^{-2\pi/\sqrt{3}})✓ Correct
  3. C.u(π/(23))=u(\pi/(2\sqrt{3})) = (1/6)(eπ/3(1/6)(e^{\pi/\sqrt{3}} −3- \sqrt{3} e−π/(23))e^{-\pi/(2\sqrt{3})})✓ Correct
  4. D.u(π/(23))=u(\pi/(2\sqrt{3})) = (1/6)(eπ/3(1/6)(e^{\pi/\sqrt{3}} +3+ \sqrt{3} e−π/3)e^{-\pi/\sqrt{3}})

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests execution slip.

See pricing

50 are analysed free — try those first.

The trap it tests

Execution slip

The idea was right. The computation was not.

Drill statements like this

Related counterexample: Every integral equation of the second kind has a unique solution

More on this topic

The chapter behind this: Integral equations: Fredholm vs Volterra — free to read

From Linear Integral Equations › Fredholm and Volterra equations

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

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