In plain words
Count the negative powers. None means the trouble was fake, finitely many means a pole, and infinitely many means essential. In practice you take a limit rather than expanding anything.
The trichotomy at an isolated singularity
| Type | Laurent principal part | Behaviour of |f| near | |
|---|---|---|---|
| Removable | none | bounded | 0 |
| Pole of order m | finitely many terms, up to | finite non-zero for m = 1 | |
| Essential | infinitely many terms | wildly oscillating | no limit |
- Riemann's removable singularity theorem: bounded near removable. Even suffices.
- Casorati–Weierstrass: near an essential singularity the image of every punctured neighbourhood is dense in .
- Picard (great): it in fact hits every value, with at most one exception, infinitely often.
Standard examples
| f | at 0 |
|---|---|
| sin z / z | removable (limit 1) |
| removable (limit ½) | |
| pole of order 3 | |
| essential | |
| sin(1/z) | essential |
| z | essential (not a pole, despite the factor z) |
| essential; residue | |
| not isolated — branch point, no Laurent series |
Computing residues
- simple pole: Res ; for f = p/q with q simple zero: .
- pole of order m: Res = (1/(m−1)!) lim .
- essential: read a₋ off the Laurent series (multiply the two series and collect .
- at : ResRes; the sum of all residues including is 0.
Laurent expansion depends on the annulus
1/((z−1)(z−2)) has three different Laurent expansions: on |z| < 1, on 1 < |z| < 2, and on |z| > 2. Exam questions always specify the annulus — read it.
Key takeaways
- Bounded ⇒ removable is the cheapest test; |f| pole.
- factors always give essential, never poles.
- The same function has different Laurent series on different annuli.