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Counterexample

Is this true?

AB and BA have the same minimal polynomial

No — it is false.

The counterexample

A = [[0,1],[0,0]], B = [[0,0],[0,1]]

Why it fails

AB = A has minimal polynomial x2x^{2}, BA = 0 has x. The characteristic polynomials do agree.

Go deeper· Explained in full in Characteristic vs minimal polynomial — what each tells you· Asked in CSIR NET December 2025· From Eigenvalues and Canonical Forms › Eigenvalues, characteristic & minimal polynomials, Cayley–Hamilton

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