NETMaths

Counterexample bank

Part C is won by knowing which tempting claims are false. 148 counterexamples; 85 free. The rest come with the Notes pack.

#1 · Complex Analysis, Algebra & Topology › Cauchy Theory

Bounded real part ⇒ entire function is constant — fails if only |f| is bounded on a half-plane— false

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complexliouville

#2 · Complex Analysis, Algebra & Topology › Singularities and Residues

Zeros of a non-constant analytic function can accumulate inside the domain— false

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complexzeros

#3 · Complex Analysis, Algebra & Topology › Singularities and Residues

|f| bounded near an isolated singularity ⇒ pole— false

Counterexample: f(z) = sin(z)/z at 0

Bounded ⇒ removable (Riemann). Poles have |f| .

complexsingularities

#4 · Complex Analysis, Algebra & Topology › Analytic Functions

The Cauchy–Riemann equations at a point imply complex differentiability there— false

Counterexample: f(z) = (z̄)²/z for z ≠ 0, f(0) = 0

CR hold at 0, but the difference quotient along z = t(1+i) differs from the one along the real axis.

complexcauchy-riemann

#5 · Complex Analysis, Algebra & Topology › Analytic Functions

A harmonic function on any domain has a harmonic conjugate— false

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complexharmonic

#6 · Complex Analysis, Algebra & Topology › Analytic Functions

Zeros of a non-constant holomorphic function cannot accumulate— false

Counterexample: sin(1/z) on ℂ∖{0}

Zeros accumulate at 0, which lies outside the domain. Inside the domain zeros are always isolated.

complexzeros

#7 · Complex Analysis, Algebra & Topology › Analytic Functions

C^∞ implies analytic— false

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complexanalyticity

#8 · Complex Analysis, Algebra & Topology › Cauchy Theory

If f is holomorphic on the domain enclosed by γ except possibly at isolated points, and ∮_γ f = 0, then f has no singularity inside— false

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complexcontour integration

#9 · Complex Analysis, Algebra & Topology › Cauchy Theory

Cauchy's theorem applies to any domain without singularities of f— false

Counterexample: f(z) = 1/z on the annulus ½ < |z| < 2

f is holomorphic there but dz — the annulus is not simply connected.

complex

#10 · Complex Analysis, Algebra & Topology › Cauchy Theory

A bounded holomorphic function on an unbounded domain is constant— false

Counterexample: f(z) = eᶻ on {Re z < 0}

|eᶻ| < 1 there, but f is not constant. Liouville needs the whole plane.

complexliouville

#11 · Complex Analysis, Algebra & Topology › Cauchy Theory

An entire function omitting one value is constant— false

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complexliouville

#12 · Complex Analysis, Algebra & Topology › Cauchy Theory

|f| attains its minimum on the boundary for holomorphic f— false

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complex

#13 · Complex Analysis, Algebra & Topology › Singularities and Residues

If |f| is bounded near an isolated singularity, the singularity is a pole— false

Counterexample: f(z) = sin z / z at 0

Bounded ⇒ removable (Riemann). Poles have |f| .

complexsingularities

#14 · Complex Analysis, Algebra & Topology › Singularities and Residues

A function has a unique Laurent expansion about a point— false

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complexlaurent

#15 · Complex Analysis, Algebra & Topology › Singularities and Residues

∮_γ f = 0 implies f is holomorphic inside γ— false

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complexresidues

#16 · Complex Analysis, Algebra & Topology › Singularities and Residues

A small indentation around a simple pole contributes 2πi·Res— false

Counterexample: The indentation at 0 when computing ∫₀^∞ sin x/x dx

A half-circle contributes Res; using gives twice the right answer.

complexresidues

#17 · Complex Analysis, Algebra & Topology › Zeros and Mappings

f′(z) ≠ 0 everywhere implies f is injective— false

Counterexample: f(z) = eᶻ on ℂ

f′ = eᶻ never vanishes, yet . Non-vanishing derivative gives only local injectivity.

complexinjectivity

#18 · Complex Analysis, Algebra & Topology › Zeros and Mappings

ℂ and the unit disc are biholomorphic (both are simply connected)— false

Counterexample: Liouville's theorem

A biholomorphism 𝔻 would invert to a bounded entire function. is the sole exception in the Riemann mapping theorem.

complexconformal