Bounded ⇒ removable (Riemann). Poles have |f| .
Counterexample bank
Part C is won by knowing which tempting claims are false. 148 counterexamples; 85 free. The rest come with the Notes pack.
#1 · Complex Analysis, Algebra & Topology › Cauchy Theory
“Bounded real part ⇒ entire function is constant — fails if only |f| is bounded on a half-plane” — false
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#2 · Complex Analysis, Algebra & Topology › Singularities and Residues
“Zeros of a non-constant analytic function can accumulate inside the domain” — false
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#3 · Complex Analysis, Algebra & Topology › Singularities and Residues
“|f| bounded near an isolated singularity ⇒ pole” — false
Counterexample: f(z) = sin(z)/z at 0
#4 · Complex Analysis, Algebra & Topology › Analytic Functions
“The Cauchy–Riemann equations at a point imply complex differentiability there” — false
Counterexample: f(z) = (z̄)²/z for z ≠ 0, f(0) = 0
CR hold at 0, but the difference quotient along z = t(1+i) differs from the one along the real axis.
#5 · Complex Analysis, Algebra & Topology › Analytic Functions
“A harmonic function on any domain has a harmonic conjugate” — false
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#6 · Complex Analysis, Algebra & Topology › Analytic Functions
“Zeros of a non-constant holomorphic function cannot accumulate” — false
Counterexample: sin(1/z) on ℂ∖{0}
Zeros accumulate at 0, which lies outside the domain. Inside the domain zeros are always isolated.
#7 · Complex Analysis, Algebra & Topology › Analytic Functions
“C^∞ implies analytic” — false
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#8 · Complex Analysis, Algebra & Topology › Cauchy Theory
“If f is holomorphic on the domain enclosed by γ except possibly at isolated points, and ∮_γ f = 0, then f has no singularity inside” — false
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#9 · Complex Analysis, Algebra & Topology › Cauchy Theory
“Cauchy's theorem applies to any domain without singularities of f” — false
Counterexample: f(z) = 1/z on the annulus ½ < |z| < 2
f is holomorphic there but dz — the annulus is not simply connected.
#10 · Complex Analysis, Algebra & Topology › Cauchy Theory
“A bounded holomorphic function on an unbounded domain is constant” — false
Counterexample: f(z) = eᶻ on {Re z < 0}
|eᶻ| < 1 there, but f is not constant. Liouville needs the whole plane.
#11 · Complex Analysis, Algebra & Topology › Cauchy Theory
“An entire function omitting one value is constant” — false
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#12 · Complex Analysis, Algebra & Topology › Cauchy Theory
“|f| attains its minimum on the boundary for holomorphic f” — false
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#13 · Complex Analysis, Algebra & Topology › Singularities and Residues
“If |f| is bounded near an isolated singularity, the singularity is a pole” — false
Counterexample: f(z) = sin z / z at 0
Bounded ⇒ removable (Riemann). Poles have |f| .
#14 · Complex Analysis, Algebra & Topology › Singularities and Residues
“A function has a unique Laurent expansion about a point” — false
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#15 · Complex Analysis, Algebra & Topology › Singularities and Residues
“∮_γ f = 0 implies f is holomorphic inside γ” — false
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#16 · Complex Analysis, Algebra & Topology › Singularities and Residues
“A small indentation around a simple pole contributes 2πi·Res” — false
Counterexample: The indentation at 0 when computing ∫₀^∞ sin x/x dx
A half-circle contributes Res; using gives twice the right answer.
#17 · Complex Analysis, Algebra & Topology › Zeros and Mappings
“f′(z) ≠ 0 everywhere implies f is injective” — false
Counterexample: f(z) = eᶻ on ℂ
f′ = eᶻ never vanishes, yet . Non-vanishing derivative gives only local injectivity.
#18 · Complex Analysis, Algebra & Topology › Zeros and Mappings
“ℂ and the unit disc are biholomorphic (both are simply connected)” — false
Counterexample: Liouville's theorem
A biholomorphism 𝔻 would invert to a bounded entire function. is the sole exception in the Riemann mapping theorem.