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Part CCSIR NET December 2023kolmogorov-scaling

Kolmogorov scaling

Let X1,…,XnX_{1}, \dots, X_{n} be a random sample from an unknown absolutely continuous CDF F, and F0aF_{0} a specified absolutely continuous CDF. For H0:F=F0H_{0}: F = F_{0} vs H1:F≠F0H_{1}: F \ne F_{0}, consider T1,nT_{1,n} = sup_x |Fn(x)−F0(x)F_{n}(x) - F_{0}(x)| and T2,nT_{2,n} = n·sup_x |Fn(x)−F0(x)F_{n}(x) - F_{0}(x)|, where FnF_{n} is the empirical CDF. Which of the following statements are true?

  1. A.T1,nT_{1,n} → 0 in probability as n→∞n \to \infty under H0H_{0}✓ Correct
  2. B.T2,nT_{2,n} → 0 in probability as n→∞n \to \infty under H0H_{0}
  3. C.lim P_F(T2,nT_{2,n} > 1) = 1 for all F✓ Correct
  4. D.T2,nT_{2,n} converges in distribution to a degenerate random variable under H0H_{0}

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests moments and tails.

See pricing

50 are analysed free — try those first.

The trap it tests

Moments and tails

A moment assumed to exist, or tail behaviour assumed to be tame.

Drill statements like this

Related counterexample: Any interval of the form [X̄ − (S/√n)t, ∞) with a 90% quantile t is a 90% confidence interval

More on this topic

The chapter behind this: Standard tests and confidence intervals — free to read

From Hypothesis Testing › Likelihood ratio and standard tests

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

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