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Part CCSIR NET December 2025both-support-constraints-are-lower-bounds-on-theta-so-the-mle-is-their-max-not-their-min

Both support constraints are lower bounds on theta so the mle is their max not their min

Let X1,X2,,Xn(n2)X_{1}, X_{2}, \dots, X_{n} (n\ge2) be a random sample from Uniform[3θ/2,θ/2][-3\theta/2, \theta/2] distribution, where θ>0\theta>0 is an unknown parameter. Let Xˉ,X(1){\bar{X}}, X_{(1)} and X(n)X_{(n)} denote respectively the mean, the smallest order statistic and the largest order statistic of the sample. Then which of the following statements are true?

  1. A.The method of moments estimator of θ\theta is −2X̄
  2. B.The method of moments estimator of θ\theta is 2X̄
  3. C.The maximum likelihood estimator of θ\theta is min{2X(1)/3,2X(n)-2X_{(1)}/3, 2X_{(n)}}
  4. D.The maximum likelihood estimator of θ\theta is max{2X(1)/3,2X(n)-2X_{(1)}/3, 2X_{(n)}}

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward.

See pricing

50 are analysed free — try those first.

Related counterexample: The MLE is unbiased

More on this topic

The chapter behind this: Maximum likelihood and the method of moments — free to read

From EstimationMLE and method of moments

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