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Part BCSIR NET December 2025root-5-splits-the-binomial-support-between-2-and-3-not-at-a-rounder-number

Root 5 splits the binomial support between 2 and 3 not at a rounder number

Let X1,X2,X_{1}, X_{2}, \dots be a sequence of independent and identically distributed random variables having Binomial(3, 1/4) distribution. For j=1,2,…, define Yj=1Y_{j} = 1 if Xj5X_{j} \le \sqrt{5}, and 0 otherwise. If (1/n)j=1n(1/n)\sum_{j=1}^n Yj2Y_{j}^{2} converges almost surely to a constant c as nn \to \infty, then the value of c equals

  1. A.1/64
  2. B.37/64
  3. C.63/64
  4. D.27/32

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward.

See pricing

50 are analysed free — try those first.

Related counterexample: Convergence in probability implies almost sure convergence

More on this topic

The chapter behind this: Modes of convergence and the limit theorems — free to read

From Limit Theorems and Markov ChainsModes of convergence, WLLN, SLLN, CLT

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

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