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Part CCSIR NET December 2025the-derivative-vanishing-at-the-root-too-signals-a-multiple-root-newtons-method-degrades-to-linear-convergence-there

The derivative vanishing at the root too signals a multiple root newtons method degrades to linear convergence there

Let {xnx_{n}} be a convergent iterative sequence generated by Newton-Raphson method for solving the equation sin x−1=0 such that xn→π/2x_{n}\to\pi/2 as n→∞n\to\infty. For n∈Nn\in\mathbb{N}, let en=xn−π/2e_{n}=x_{n}-\pi/2. Let p>0 be such that lim⁡(n→∞)\lim(n\to\infty)|ene_{n}₊1_{1}|/|ene_{n}|^p exists and is non-zero. Then which of the following statements are true?

  1. A.p = 1✓ Correct
  2. B.lim⁡(n→∞)\lim(n\to\infty) |ene_{n}₊1_{1}|/|ene_{n}|^p = 1/2✓ Correct
  3. C.p = 2
  4. D.lim⁡(n→∞)\lim(n\to\infty) |ene_{n}₊1_{1}|/|ene_{n}|^p = 1

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests numerical convergence.

See pricing

50 are analysed free — try those first.

The trap it tests

Numerical convergence

A scheme assumed to converge, or to converge at its advertised rate.

Drill statements like this

Related counterexample: Newton's method converges quadratically to any root

More on this topic

The chapter behind this: Root finding and orders of convergence — free to read

From Numerical Analysis › Root finding: bisection, Newton–Raphson, fixed point, order of convergence

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