The finite population correction n minus n over n minus 1 is what links the two variances

Consider a finite population of size N = 100. Let $T_{1}$ be the sample mean of a study variable based on a sample of size n (1 < n < N) under simple random sampling with replacement scheme. Let $T_{2}$ be the sample mean of the same study variable based on a sample of size n under simple random sampling without replacement scheme. If $Var(T_{1}) = 9Var(T_{2})$, then the sample size n equals