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Part BCSIR NET June 2024conditioning-is-a-measure-only-for-fixed-condition

Conditioning is a measure only for fixed condition

Let A1,A2,A3A_{1}, A_{2}, A_{3} be events satisfying 0<P(Ai)<10 < P(A_{i}) < 1 for i = 1, 2, 3. Which of the following statements is true?

  1. A.P(A1P(A_{1} | A2)P(A2A_{2})P(A_{2} | A3)≤P(A1A_{3}) \le P(A_{1} | A3)A_{3})
  2. B.P(A1P(A_{1} | A2)P(A3A_{2})P(A_{3} | A2)≥P(A1∩A3A_{2}) \ge P(A_{1} \cap A_{3} | A2)A_{2})
  3. C.P(A1P(A_{1} | A2)+P(A3A_{2}) + P(A_{3} | A2)≥P(A1∪A3A_{2}) \ge P(A_{1} \cup A_{3} | A2)A_{2})✓ Correct
  4. D.P(A1P(A_{1} | A2)+P(A2A_{2}) + P(A_{2} | A3)≤P(A1A_{3}) \le P(A_{1} | A3)A_{3})

You have the answer. Trap Analysis is why the other three were written.

Not a worked solution repeated four times — the specific reasoning error each wrong option was built to reward, and why this one tests dependence misread.

See pricing

50 are analysed free — try those first.

The trap it tests

Dependence misread

Independence, pairwise vs mutual, or correlation vs dependence.

Drill statements like this

Related counterexample: Pairwise independent events are mutually independent

More on this topic

The chapter behind this: Probability axioms, conditioning and independence — free to read

From Probability › Axioms, conditional probability, independence, Bayes

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

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