Converse of Lagrange: d | |G| ⇒ subgroup of order d
Is this true?
No — it is false.
Others that fail the same way
From Groups › Normal subgroups, quotients, isomorphism theorems
Is this true?
Converse of Lagrange: d | |G| ⇒ subgroup of order d
No — it is false.
From Groups › Normal subgroups, quotients, isomorphism theorems