Conjugating (12)(34) by the 3-cycle (123) gives (13)(24) ∉ ⟨(12)(34)⟩.
Counterexample bank
Part C is won by knowing which tempting claims are false. 148 counterexamples; 85 free. The rest come with the Notes pack.
#1 · Complex Analysis, Algebra & Topology › Groups
“Converse of Lagrange: d | |G| ⇒ subgroup of order d” — false
Counterexample: A₄ has no subgroup of order 6
#2 · Complex Analysis, Algebra & Topology › Groups
“H ⊴ K and K ⊴ G ⇒ H ⊴ G” — false
Counterexample locked — unlock with Notes + PYQ
#3 · Complex Analysis, Algebra & Topology › Groups
“Every group of order p² is cyclic” — false
Counterexample locked — unlock with Notes + PYQ
#4 · Complex Analysis, Algebra & Topology › Groups
“If d divides |G| then G has a subgroup of order d” — false
Counterexample: A₄ has order 12 but no subgroup of order 6
#5 · Complex Analysis, Algebra & Topology › Groups
“o(ab) is finite whenever o(a) and o(b) are” — false
Counterexample locked — unlock with Notes + PYQ
#6 · Complex Analysis, Algebra & Topology › Groups
“H ⊴ K and K ⊴ G imply H ⊴ G” — false
Counterexample: ⟨(12)(34)⟩ ⊴ V₄ ⊴ A₄
#7 · Complex Analysis, Algebra & Topology › Groups
“If every subgroup of G is normal then G is abelian” — false
Counterexample locked — unlock with Notes + PYQ
#8 · Complex Analysis, Algebra & Topology › Groups
“Aₙ is simple for every n ≥ 3” — false
Counterexample: A₄ has the normal subgroup V₄ = {e, (12)(34), (13)(24), (14)(23)}
#9 · Complex Analysis, Algebra & Topology › Groups
“A group with trivial centre cannot have order a prime power” — false
Counterexample locked — unlock with Notes + PYQ
#10 · Complex Analysis, Algebra & Topology › Groups
“G/Z(G) can be cyclic and non-trivial” — false
Counterexample: Impossible — if G/Z is cyclic then G is abelian, so G/Z is trivial
This 'no counterexample exists' fact is itself examined: |G/Z| is never prime.
#11 · Complex Analysis, Algebra & Topology › Groups
“A group of order pq (p < q) is always cyclic” — false
Counterexample: S₃ of order 6 = 2·3
Non-abelian because 2 | 3 − 1. The cyclic conclusion needs p ∤ q − 1.
#12 · Complex Analysis, Algebra & Topology › Groups
“(ℤ/2^kℤ)* is cyclic for every k” — false
Counterexample locked — unlock with Notes + PYQ