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Counterexample

Is this true?

Newton's method always converges from any starting point

No — it is false.

The counterexample

The object that kills this claim comes with Trap Analysis.

See pricing

86 counterexamples are free — including most of the ones Part C leans on hardest.

Go deeper· Explained in full in Root finding and orders of convergence· Asked in CSIR NET December 2025· From Numerical Analysis › Root finding: bisection, Newton–Raphson, fixed point, order of convergence

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